(5x^2+15x-25)/5x=0

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Solution for (5x^2+15x-25)/5x=0 equation: 



(5x^2+15x-25)/5x=0



Domain of the equation: 5x!=0

x!=0/5

x!=0

x∈R



We multiply all the terms by the denominator


(5x^2+15x-25)=0

We get rid of parentheses

5x^2+15x-25=0

a = 5; b = 15; c = -25;
Δ = b2-4ac
Δ = 152-4·5·(-25)
Δ = 725
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:


$\sqrt{\Delta}=\sqrt{725}=\sqrt{25*29}=\sqrt{25}*\sqrt{29}=5\sqrt{29}$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-5\sqrt{29}}{2*5}=\frac{-15-5\sqrt{29}}{10}
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+5\sqrt{29}}{2*5}=\frac{-15+5\sqrt{29}}{10}
$

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